68 lines
1.8 KiB
Bash
68 lines
1.8 KiB
Bash
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#From: "dennis" <dennis@netstrata.com>
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#To: <bash-maintainers@gnu.org>
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#Subject: New example script: bash-hexdump
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#Date: Mon, 4 Jan 2010 22:48:19 -0700
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#Message-ID: <6dbec42d$64fcdbd2$4a32cf2d$@com>
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#I've written a script that functions like "hexdump -C" or "hd". If you'd
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#like to include it in a future distribution of example Bash scripts, I have
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#included it here:
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#!/bin/bash
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# bash-hexdump# pure Bash, no externals
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# by Dennis Williamson - 2010-01-04
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# in response to
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http://stackoverflow.com/questions/2003803/show-hexadecimal-numbers-of-a-file
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# usage: bash-hexdump file
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saveIFS="$IFS"
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IFS="" # disables interpretation of \t, \n and space
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saveLANG="$LANG"
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LANG=C # allows characters > 0x7F
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bytecount=0
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valcount=0
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printf "%08x " $bytecount
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while read -d '' -r -n 1 char # -d '' allows newlines, -r allows \
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do
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((bytecount++))
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# for information about the apostrophe in this printf command, see
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# http://www.opengroup.org/onlinepubs/009695399/utilities/printf.html
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printf -v val "%02x" "'$char"
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echo -n "$val "
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((valcount++))
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if [[ "$val" < 20 || "$val" > 7e ]]
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then
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string+="." # show unprintable characters as a dot
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else
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string+=$char
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fi
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if (( bytecount % 8 == 0 )) # add a space down the middle
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then
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echo -n " "
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fi
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if (( bytecount % 16 == 0 )) # print 16 values per line
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then
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echo "|$string|"
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string=''
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valcount=0
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printf "%08x " $bytecount
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fi
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done < "$1"
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if [[ "$string" != "" ]] # if the last line wasn't full, pad it out
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then
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length=${#string}
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if (( length > 7 ))
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then
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((length--))
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fi
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(( length += (16 - valcount) * 3 + 4))
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printf "%${length}s\n" "|$string|"
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printf "%08x " $bytecount
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fi
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echo
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LANG="$saveLANG";
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IFS="$saveIFS"
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exit 0
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